1 solutions
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0
C++ :
#include<bits/stdc++.h> using namespace std; int n,a[10005],b[10005],x,ans; int main() { cin>>n; for(int i=1;i<=2;i++) { cin>>x; a[i]=x; b[x]++; } for(int i=3;i<=n;i++) { cin>>x; for(int j=1;j<i;j++) { int y=x-a[j]; if(y>0){ if(a[j]==y && b[y]==1) continue; if(b[y]>0) {ans++;break;} } } a[i]=x; b[x]++; } cout<<ans; return 0; } /* 8 5 2 2 3 4 8 7 5 */
- 1
Information
- ID
- 976
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
- Uploaded By