1 solutions

  • 0
    @ 2025-12-3 17:01:24

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int r,a[105],n,m,sum;
    int main()
    {
    	cin>>r;
    	while(r--)
    	{
    		cin>>n>>m;
    		sum=0;
    		for(int i=1;i<=m;i++)
    		{
    			cin>>a[i];	
    			sum+=a[i];		
    		}
    		if(sum%n!=0) {cout<<"impossible"<<endl;continue;}
    		sum/=n;
    		sort(a+1,a+1+m);
    		int bj=0;
    		for(int i=m,j=1;i>=j;)
    		{
    			if(a[i]>sum) {bj=1;break;}
    			if(a[i]==sum) i--;
    			if(a[i]<sum && a[i]+a[j]>sum) {bj=1;break;}
    			if(a[i]<sum && a[i]+a[j]<sum) {bj=1;break;}
    			if(a[i]<sum && a[i]+a[j]==sum) i--,j++;
    		}
    		if(bj==1) cout<<"impossible"<<endl;
    		else cout<<"possible"<<endl;
    	}
        return 0; 
    } 
    
    
    • 1

    Information

    ID
    944
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    10
    Tags
    # Submissions
    1
    Accepted
    1
    Uploaded By