1 solutions
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0
C++ :
#include<bits/stdc++.h> using namespace std; int n,da[1000005],xiao[1000005],q,x,da1,xiao1=1000000005; int main() { cin>>n; for(int i=1;i<=n;i++) { scanf("%d",&x); if(x>da1) da1=x; da[i]=da1; if(x<xiao1) xiao1=x; xiao[i]=xiao1; } cin>>q; while(q--) { scanf("%d",&x); printf("%d ",da[x]-xiao[x]); } return 0; }
- 1
Information
- ID
- 911
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 10
- Tags
- # Submissions
- 1
- Accepted
- 1
- Uploaded By