1 solutions

  • 0
    @ 2025-12-3 16:44:26

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int n,da[1000005],xiao[1000005],q,x,da1,xiao1=1000000005;
    int main()
    {
    	cin>>n;
    	for(int i=1;i<=n;i++)
    	{
    		scanf("%d",&x);
    		if(x>da1) da1=x;
    		da[i]=da1;
    		if(x<xiao1) xiao1=x;
    		xiao[i]=xiao1;
    	}
    	cin>>q;
    	while(q--)
    	{
    		scanf("%d",&x);
    		printf("%d ",da[x]-xiao[x]);
    	}
        return 0;
    }
    
    • 1

    Information

    ID
    911
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    10
    Tags
    # Submissions
    1
    Accepted
    1
    Uploaded By