1 solutions

  • 0
    @ 2025-12-3 16:44:25

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    long long n,x,a[100005],sum,ans;
    int main(){
    	cin>>n>>x;
    	for(int i=1;i<=n;i++)
    		cin>>a[i],sum+=a[i];
    	ans=x/sum*n;
    	sum*=x/sum;
    	if(sum>=x) {cout<<ans;return 0;}
    	for(int i=1;i<=n;i++)
    	{
    		sum+=a[i];
    		if(sum>=x) {cout<<ans+i;return 0;}
    	}
        return 0;
    }
    
    • 1

    Information

    ID
    903
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    10
    Tags
    # Submissions
    1
    Accepted
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