1 solutions
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0
C++ :
#include<bits/stdc++.h> using namespace std; long long n,x,a[100005],sum,ans; int main(){ cin>>n>>x; for(int i=1;i<=n;i++) cin>>a[i],sum+=a[i]; ans=x/sum*n; sum*=x/sum; if(sum>=x) {cout<<ans;return 0;} for(int i=1;i<=n;i++) { sum+=a[i]; if(sum>=x) {cout<<ans+i;return 0;} } return 0; }
- 1
Information
- ID
- 903
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 10
- Tags
- # Submissions
- 1
- Accepted
- 1
- Uploaded By