1 solutions
-
0
C++ :
#include<bits/stdc++.h> using namespace std; long long a,b,c,k,aa,bb; int main(){ cin>>a>>b>>c>>k; for(long long i=a;;i++) if(i%c==0) {aa=i;break;} for(long long i=b;;i--) if(i%c==0) {bb=i;break;} long long ans1=(bb-aa)/c+1; long long ans2=aa+c*(k-1); cout<<ans1<<" "<<ans2; return 0; }
- 1
Information
- ID
- 902
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 10
- Tags
- # Submissions
- 4
- Accepted
- 2
- Uploaded By