1 solutions

  • 0
    @ 2025-12-3 16:19:45

    C++ :

    #include<iostream>
    #include<algorithm>
    using namespace std;
    int n,a[10008],mx,mxx,l,s;
    int main()
    {
    	cin>>n;
    	for (int i=1;i<=n;i++){
    		cin>>a[i];
    		if (a[i]>mx) {mx=a[i];l=i;}
    	}
    	for (int i=1;i<=n;i++)
    	 if (a[i]<mx&&a[i]>mxx) {mxx=a[i];s=i;}
    	 cout<<abs(l-s)*10<<endl;
    	return 0;
    }
    
    • 1

    Information

    ID
    863
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    10
    Tags
    # Submissions
    3
    Accepted
    3
    Uploaded By