1 solutions

  • 0
    @ 2025-12-3 16:19:45

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int n,a[100005],b[100005],sum=0;
    int main()
    {
    	cin>>n;
    	for(int i=1;i<=n;i++){
    		cin>>a[i];
    	}
    	for(int i=n;i>=1;i--){
    		sum++;
    		b[i]=a[sum];
    	}
    	for(int i=1;i<=n;i++){
    		cout<<b[i]<<" ";
    	}
    	return 0;
    }
    
    • 1

    Information

    ID
    854
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    10
    Tags
    # Submissions
    3
    Accepted
    3
    Uploaded By