1 solutions
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0
C++ :
#include<bits/stdc++.h> using namespace std; int work(int x,int y) { int c=x%y,ans=0; if(c==0) ans=0; else ans=(x/y+1)*y-x; return ans; } int n,a,b; int main() { // freopen("1016.in","r",stdin); // freopen("1016.out","w",stdout); cin>>n>>a>>b; int a1=work(n,a),b1=work(n,b); cout<<min(a1,b1); return 0; }
- 1
Information
- ID
- 779
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 10
- Tags
- # Submissions
- 2
- Accepted
- 1
- Uploaded By