1 solutions
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1
C++ :
#include<bits/stdc++.h> using namespace std; int n,x,a[100005]; void f() { for(int i=2;i<=sqrt(100000);i++) if(a[i]==0) for(int j=i*i;j<=100000;j+=i) a[j]=1; a[0]=a[1]=1; } int main() { // freopen("5.in","r",stdin); // freopen("5.out","w",stdout); f(); cin>>n; while(n--) { cin>>x; cout<<a[x]<<endl; } return 0; }
- 1
Information
- ID
- 726
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 8
- Tags
- # Submissions
- 32
- Accepted
- 7
- Uploaded By