1 solutions

  • 1
    @ 2025-12-2 16:13:53

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int n,x,a[100005];
    void f()
    {
    	for(int i=2;i<=sqrt(100000);i++)
    		if(a[i]==0)
    			for(int j=i*i;j<=100000;j+=i)
    				a[j]=1;
    	a[0]=a[1]=1;
    }
    int main()
    {
    //	freopen("5.in","r",stdin);
    //	freopen("5.out","w",stdout);
    	f();
    	cin>>n;
    	while(n--)
    	{
    		cin>>x;
    		cout<<a[x]<<endl;
    	}
        return 0;
    }
    
    • 1

    Information

    ID
    726
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    8
    Tags
    # Submissions
    32
    Accepted
    7
    Uploaded By