2 solutions

  • 0
    @ 2025-11-21 15:10:46

    解题报告

    撰写人: 许苡键

    难度等级

    ★★☆☆☆

    参考程序

    #include <bits/stdc++.h>
    using namespace std;
    int main(){
    	long long n,m;
    	cin>>n;
    	long long a[n+1],b[n+1],d=99999;
    	b[0]=0;
    	for(int i=1;i<=n;i++){
    		cin>>a[i];
    		b[i]=b[i-1]+a[i];
    	}
    	for(int i=1;i<=n;i++){
    		if(max(b[i],b[n]-b[i])-min(b[i],b[n]-b[i])<d){
    			d=max(b[i],b[n]-b[i])-min(b[i],b[n]-b[i]);
    		}
    	}
    	cout<<d;
    }
    
    • 0
      @ 2025-11-18 20:05:56

      C++ :

      #include<bits/stdc++.h>
      using namespace std;
      long long n,a[100005],b[100005],minx=10000000000000001;
      int main()
      {
      	cin>>n;
      	for(int i=1;i<=n;i++)
      	{
      		cin>>a[i];
      		b[i]=b[i-1]+a[i];
      	}
      	for(int i=1;i<=n;i++)
      	{
      		if(max(b[i],b[n]-b[i])-min(b[i],b[n]-b[i])<minx){minx=max(b[i],b[n]-b[i])-min(b[i],b[n]-b[i]);
      		}
      	}
      	cout<<minx;
      	return 0;
      }
      
      • 1

      Information

      ID
      612
      Time
      1000ms
      Memory
      128MiB
      Difficulty
      5
      Tags
      # Submissions
      39
      Accepted
      15
      Uploaded By