1 solutions
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0
C++ :
#include<bits/stdc++.h> using namespace std; int a[27],bj; string s; int main() { cin>>s; for(int i=0;i<s.size();i++) { if(s[i]>='A' && s[i]<='Z'){ int x=(int)s[i]-64; a[x]++; bj=1; } } if(bj==0) {cout<<0;return 0;} for(int i=1;i<=26;i++) { if(a[i]>0) cout<<(char)(i+64)<<':'<<a[i]<<endl; } return 0; }
- 1
Information
- ID
- 1088
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 10
- Tags
- # Submissions
- 2
- Accepted
- 1
- Uploaded By