1 solutions

  • 0
    @ 2025-12-25 16:00:31

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int a[27],bj;
    string s;
    int main()
    {   
    	cin>>s;
    	for(int i=0;i<s.size();i++)
    	{
    		if(s[i]>='A' && s[i]<='Z'){
    			int x=(int)s[i]-64;
    			a[x]++;
    			bj=1;
    		}
    	}
    	if(bj==0) {cout<<0;return 0;}
    	for(int i=1;i<=26;i++)
    	{
    		if(a[i]>0) cout<<(char)(i+64)<<':'<<a[i]<<endl;
    	}
        return 0;    
    }
    
    
    • 1

    Information

    ID
    1088
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    10
    Tags
    # Submissions
    2
    Accepted
    1
    Uploaded By