1 solutions
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0
C++ :
#include<bits/stdc++.h> using namespace std; string s; long long ans; int main() { cin>>s; int len=s.size(); for(int i=0;i<len;) { if(s[i]>='0' && s[i]<='9') { long long sum=s[i]-'0'; for(int j=i+1;;) { if(j==len) {i=len,ans+=sum;break;}//防止最后一位是数字 if(s[j]>='0' && s[j]<='9') {sum=sum*10+(s[j]-'0');j++;} else {ans+=sum,i=j+1;break;} } } else i++; } cout<<ans; return 0; }
- 1
Information
- ID
- 1054
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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