1 solutions
-
0
C :
#include<stdio.h> main() { int t; int i; int a[10000]; scanf("%d",&t); for(i=0;i<t;i++) { scanf("%d",&a[i]); } for(i=0;i<t;i++) { printf("%c",a[i]); } printf("\n"); }C++ :
#include<iostream> using namespace std; int main() { int n,a; char t; cin>>n; for(int i=1;i<=n;i++) { cin>>a;t=a; cout<<t; } return 0; }
- 1
Information
- ID
- 1030
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 10
- Tags
- # Submissions
- 1
- Accepted
- 1
- Uploaded By