1 solutions

  • 0
    @ 2025-12-3 17:27:33

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int n,ans,a[200005];
    long long sum1[200005],sum2[200005];
    int main(){
        cin>>n;
        for(int i=1;i<=n;i++)
        {
        	cin>>a[i];
        	if(i%2==1)
    		{
    			sum1[i]=sum1[i-1]+a[i];
    			sum2[i]=sum2[i-1];
    		}
    		else
    		{
    			sum2[i]=sum2[i-1]+a[i];
    			sum1[i]=sum1[i-1];
    		}
    	}
    	for(int i=1;i<=n;i++)
    	{
    		if(i%2==1)
    		{
    			if(sum1[i-1]+(sum2[n]-sum2[i]) == sum2[i]+(sum1[n]-sum1[i]))
    				ans++;
    		}
    		else
    		{
    			if(sum1[i]+(sum2[n]-sum2[i+1]) == sum2[i-1]+(sum1[n]-sum1[i]))
    				ans++;
    		}
    	}
    	cout<<ans;
        return 0;
    }
    
    • 1

    Information

    ID
    1005
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    9
    Tags
    # Submissions
    9
    Accepted
    4
    Uploaded By