1 solutions

  • 0
    @ 2025-12-3 17:21:29

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    int n,a[1010],b[1010],m,sum,x;
    int main()
    {
    	cin>>n;
    	for(int i=1;i<=n;i++)
    	{
    		cin>>a[i]>>b[i];
    		sum+=a[i];
    		a[i]=a[i-1]+a[i];
    	}
    	cin>>m;
    	while(m--)
    	{
    		cin>>x;
    		if(x%sum==0) {cout<<b[n]<<" ";continue;}
    		x%=sum;
    		for(int i=1;;i++)
    			if(x<=a[i]) {cout<<b[i]<<" ";break;}	
    	}
    	return 0;
    }
    
    
    • 1

    Information

    ID
    1000
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    10
    Tags
    # Submissions
    1
    Accepted
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