1 solutions

  • 0
    @ 2025-12-2 13:52:11

    非常的简单好吧 因为懒 so:

    
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
       string s;
       int ans=0;
       cin>>s;
       for(int i=0;i<s.size();i++)
       {
          if(s[i]=='a')ans+=1;
          if(s[i]=='b')ans+=3;
          if(s[i]=='c')ans+=5;
          if(s[i]=='d')ans+=7;
          if(s[i]=='e')ans+=9;
          if(s[i]=='f')ans+=11;
          if(s[i]=='g')ans+=13;
          if(s[i]=='h')ans+=15;
          if(s[i]=='i')ans+=17;
          if(s[i]=='j')ans+=19;
          if(s[i]=='k')ans+=21;
          if(s[i]=='l')ans+=23;
          if(s[i]=='m')ans+=25;
          if(s[i]=='n')ans+=27;
          if(s[i]=='o')ans+=29;
          if(s[i]=='p')ans+=31;
          if(s[i]=='q')ans+=33;
          if(s[i]=='r')ans+=35;
          if(s[i]=='s')ans+=37;
          if(s[i]=='t')ans+=39;
          if(s[i]=='u')ans+=41;
          if(s[i]=='v')ans+=43;
          if(s[i]=='w')ans+=45;
          if(s[i]=='x')ans+=47;
          if(s[i]=='y')ans+=49;
          if(s[i]=='z')ans+=51;
       }
       cout<<ans;
       return 0;
    }
    

    简单的暴力枚举

    Information

    ID
    637
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    8
    Tags
    # Submissions
    14
    Accepted
    8
    Uploaded By